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View Full Version : Why the two defence values?


Der Panzinator
06-25-2005, 10:31 PM
I'm trying to figure out why there is two defence values printed on the unit cards. For defence value it always has a x/x value... I know that you roll the number of 6 sided dice listed on the card based on distance in hexes to target. And then you count hits for any 4, 5, 6. But then you compare to the defence value and that is where I'm at a loss. Is one number the damaged value and the other the destroyed value. Or is one for defence against artillery and the other for everything else. Or is it something else???

Anyone have any ideas?

SeattleGamer
06-26-2005, 12:12 AM
From Richard Baker (Attack Mechanic thread)

Here's the quick synopsis:

1. Roll a number of D6 equal to your attack value for the range.

2. Count up the number of 4+ results.

3. Compare this total to the target's armor rating. For soldiers, it doesn't matter which way they were facing. But vehicles have front armor and rear armor, and those numbers may be very different.

4. If the number of hits = the target's armor, you'll disrupt it. If the number of hits exceeds the target's armor, you'll damage it (a vehicle already damaged is destroyed by a second damage result). If the number of hits = twice the target's armor, you destroy it all in one go. Soldiers can't be damaged--they're either disrupted or dead.

5. Assuming you don't get hit again next turn, you'll shake off your disrupted result. But damage lasts forever, at least in the context of our game.

Hope that helps.

So it would look like the two values are front & side/rear armor values.